If $x^2 + 2ax + 10 - 3a > 0$ for all $x ∈ R$, then

✅ Correct Answer: -5 < a < 2

Explanation

For quadratic always positive, discriminant < 0: $(2a)^2 - 4(10-3a) < 0$. Solving gives $-5 < a < 2$.

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If $x^2 + 2ax + 10 - 3a > 0$ for all $x ∈ R$, then | ACME Academy