If $f(\sin x) - f(-\sin x) = x^2 - 1$ is defined for all $x \in \mathbb{R}$, then the value of $x^2 - 2$ can be

✅ Correct Answer: -1

Explanation

Since the expression is valid for all $x$, evaluating gives $x^2 - 2 = -1$ when $x^2 = 1$.

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If $f(\sin x) - f(-\sin x) = x^2 - 1$ is defined for all $x \in \mathbb{R}$, then the value of $x^2 - 2$ can be | ACME Academy