Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
- A. 1/(2)
- B. 2/(5)
- C. 8/(15)
- D. 9/(20)
✅ Correct Answer: 9/(20)
Explanation
Here, S={1, 2, 3, 4, ...., 19, 20}. Let E=event of getting a multiple of 3 or 5={3, 6 , 9, 12, 15, 18, 5, 10, 20}. [https://www.indiabix.com/_files/images/aptitude/1-sym-tfr.gif] P(E)=n(E)/(n(S))=
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