The value of $\lim_{x \to 0} (e^x - e^{-x} - 2x)/(1 - \cos x)$ is
- A. 2
- B. 1
- C. 0
- D. -1
✅ Correct Answer: 0
Explanation
The limit is of the form $0/0$ Apply L'Hospital rule $(e^x + e^{-x} - 2)/(\sin x)$ Again $0/0$ Apply L'Hospital rule $(e^x - e^{-x})/(\cos x)$ Substitute $x = 0$ Value $= 0$
🎯 Happy Preparation — ACME Academy
