The mean of consecutive positive integers from 2 to n is

Explanation

Sum of numbers from $1$ to $n$ is $\frac{n(n+1)}{2}$ Sum of numbers from $2$ to $n$ $= \frac{n(n+1)}{2} - 1$ Total numbers $= n - 1$ Mean $= \frac{\frac{n(n+1)}{2} - 1}{n-1} = \frac{n+2}{2}$