The inradius of a triangle with sides 3, 5, and 6 is
- A. $\sqrt{\frac{8}{7}}$
- B. $\sqrt{8}$
- C. $\sqrt{7}$
- D. $\sqrt{\frac{7}{8}}$
✅ Correct Answer: $\sqrt{\frac{8}{7}}$
Explanation
Using Heron’s formula and $r = \frac{\Delta}{s}$ gives $r = \sqrt{\frac{8}{7}}$.
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