The differential equation $(e^x + 1)y\,dy = (y + 1)e^x\,dx$ has the solution
- A. $(y - 1)(e^x - 1) = ce^y$
- B. $(y - 1)(e^x + 1) = ce^y$
- C. $(y + 1)(e^x - 1) = ce^y$
- D. $(y + 1)(e^x + 1) = ce^y$
✅ Correct Answer: $(y + 1)(e^x + 1) = ce^y$
Explanation
By separating variables, we get $(y + 1)(e^x + 1) = ce^y$ as the final solution.
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