A point moves along the curve $12y = x^3$ such that rate of increase of ordinate is greater than that of abscissa. Then abscissa lies in

✅ Correct Answer: $(-\infty, -2) \cup (2, \infty)$

Explanation

Differentiating gives $\frac{dy}{dx} = \frac{x^2}{4}$. For $\frac{dy}{dt} > \frac{dx}{dt}$, we need $x^2/4 > 1 \Rightarrow |x| > 2$.

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A point moves along the curve $12y = x^3$ such that rate of increase of ordinate is greater than that of abscissa. Then abscissa lies in | ACME Academy