A coin is thrown $8$ times. What is the probability of getting a head in an odd number of throws?

✅ Correct Answer: 1/2

Explanation

In one throw of a coin, the number of possible outcomes is $2$ In $n$ throws, total outcomes $= 2^n$ Here $n = 8$ Number of favourable outcomes $= {}^8C_1 + {}^8C_3 + {}^8C_5 + {}^8C_7$ $= 2^{7}$ Required probability $= 2^{7} / 2^{8} = 1/2$

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