A bag contains n white and n black balls. Pairs are drawn without replacement. The probability that each pair has one white and one black ball is
- A. 1 / C(2n, n)
- B. 2n / C(2n, n)
- C. 2n / n!
- D. 2n / (2n)!
✅ Correct Answer: 1 / C(2n, n)
Explanation
All pairs must be mixed. Total arrangements = C(2n, n). Only one favourable arrangement exists. Hence probability = 1 / C(2n, n).
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